| One gm –mole of Heat S.T. P= 22.4 lit Case 2: – molar volume at R.T.P = 24.45 lit One gm-mole oxygen at R.T.P = 22.45 lit One gm-atom of Heat R.T.P =22.45 lit Unit of volume M3 ,dm3, cm3 1m = 10dm = 100cm 1m3 =1000m3 (lit ) = 106cm3(cc) 1m3 = 1000lit 1lit = 1000cc = 1000ml Density: – Mass per unit volume is called density. Density = mass/volume = Unit = gm/cc, gm/lit, kg /m3 D = 1010kg /m3 =1010x1000gm/1000lit = 1010gm / it =1010gm/1000cc = 1.010gm/cc Density of H2o d = 1gm / cc Question:- calculate the total no of atoms in 11.2 lit of oxygen of S.T.P Solution:- One gm-mole oxygen = 32gm = 22.4lit = 3.011x1023mlecular 11.2 lit = 3.011×1023 1molecular = 2atom = 3.011×1023 x2 = 6.022×1023 Measurable properties of gas· (1) Mass Unit = gm, kg, mole (2) Volume The volume of gas = volume of the vessel M =VX d Page no.-06 Unit of volume = m3, dm3(lit) cm3(cc) (3) pressure = force/area Unit of pressure 1atom pressure = 76m of Hg = 760mm of Hg = 1.01×105 N / m2(or) pa = 1.01×106 dyne /cm2 = 760 bar = 1.013 bar (4) Temperature Unit = 00c and Kelvin k = t0c+273 PV = NRT P = pressure in atom unit V = volume in lit N = mole of gas T = temperature in Kelvin R = molar gas constant = 0.0821 lit – atm/mole /k PV = W/M RT W = wt. of gas in gm M = M.W of gas Relation between mass and mole· No f mole = mass given in gm /formula wt. No of gm-atom = mass given in gm /AT Wt. No of gm-mole = mass given in gm /M. W No of gm-ion = mass given in gm /ionic wt. Relation between volume and mole· No of mole = volume in lit at S.T.P / 22.4 = volume in lit at R.T.P / 24.4m Relation between number and mole
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